Webb17 sep. 2024 · Prove the following: sin (50° + θ ) – cos (40° – θ ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89° = 1 asked Feb 16, 2024 in Mathematics by sforrest072 ( 129k … WebbClick here👆to get an answer to your question ️ the value of tan 20 ^∘ + 2 tan 50 ^∘ - tan 70 ^∘ is : Solve Study Textbooks Guides. Join / Login >> Class 11 >> Maths >> Trigonometric Functions >> Trigonometric Functions of Sum and Difference of Two angles >> the value of tan 20 ^∘ + 2 tan 50 ^∘ - t.
prove that tan 70° = tan 20° + 2 tan 50° - BYJU
Webb6 jan. 2015 · Ramesh 70 - 20 = 50 By applying tan on both sides, we get ⇒ Tan ( 70 - 20) = Tan 50 ⇒ (Tan 70 - Tan 20) / ( 1 + Tan 70.Tan 20) = Tan 50 ⇒ (Tan 70 - Tan 20) / ( 1 + Tan 70.Tan (90 -70)) = Tan 50 ⇒ (Tan 70 - Tan 20) / ( 1 + Tan 70.Cot 70) = Tan 50 [ Tan 70.Cot 70 = 1] ⇒ (Tan 70 - Tan 20) / ( 1 + 1) = Tan 50 ⇒ (Tan 70 - Tan 20) = 2Tan 50 Webbtan 70 = tan ( 20 + 50) ∵ t a n ( A + B) = ( tan A + tan B) 1 – tan A tan B ⇒ tan 70 = ( tan 20 + tan 50) 1 – tan 20 tan 50 ⇒ tan 70 ( 1 – tan 20 tan 50) = tan 20 + tan 50 ⇒ tan 70 – tan 70 tan 20 tan 50 = tan 20 + tan 50 ⇒ tan 70 − tan 50 = tan 20 + tan 50 ( ∵ tan 70 tan 20 = 1) ⇒ tan 70 = tan 20 + 2 tan 50 Hence proved. Suggest Corrections 0 ccsoh fort hayes
Prove that: (i) sin (50° + θ)cos(20° + θ) - cos(50° + θ)sin(20° + θ ...
WebbClick here👆to get an answer to your question ️ Prove: tan 20^o + tan 25^o + tan 20^otan 25^o = 1 . Solve Study Textbooks Guides. Join / Login >> Class 11 >> Maths >> Trigonometric Functions >> Trigonometric Equations >> Prove: tan 20^o + tan 25^o + tan 20^otan. Question . Prove: tan 2 0 o + tan 2 5 o + tan 2 0 o tan 2 5 o = 1. Medium. Open ... Webb6 feb. 2024 · tan 70° = tan (50° + 20°) ⇒ tan 70° =tan50°+tan20° 1−tan50°tan20° t a n 50 ° + t a n 20 ° 1 − t a n 50 ° t a n 20 °. [∵ tan (A + B) =tanA+tanB 1−tanAtanB t a n A + t a n B … Webb20 apr. 2024 · Best answer LHS = tan 70∘ = tan(20∘ + 50 ∘) = tan 20∘ + tan 50∘ 1 − tan 20 ∘ tan 50 ∘ = tan 70 ∘ = tan ( 20 ∘ + 50 ∘) = tan 20 ∘ + tan 50 ∘ 1 - tan 20 ∘ tan 50 ∘ or tan 70∘ − tan 20∘ tan 50∘ tan 70∘ = tan 20∘ + tan 50∘ tan 70 ∘ - tan 20 ∘ tan 50 ∘ tan 70 ∘ = tan 20 ∘ + tan 50 ∘ = cot 70∘ + 2cot 40∘ = cot 70 ∘ + 2 cot 40 ∘ =RHS butcher fancy mclean ave yonkers